What are the solutions to the equation x^2-24x+36=0 ?

The solutions to the equation x^2-24x+36=0 are x=6(2+sqrt(3)),x=6(2-sqrt(3))

Find the zeros of x^2-24x+36=0

The zeros of x^2-24x+36=0 are x=6(2+sqrt(3)),x=6(2-sqrt(3))

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x^{2} - 24 x + 36 = 0

x = 6 (2 + 3), x = 6 (2 - 3)

Decimal Notation

x = 22.39230 \dots, x = 1.60769 \dots

Solution steps

x^{2} - 24 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

(- 24)^{2} - 4 \cdot 1 \cdot 36 = 123

x_{1, 2} = \frac{- ( - 24 ) \pm 12 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 12 3}{2 \cdot 1}, x_{2} = \frac{- ( - 24 ) - 12 3}{2 \cdot 1}

x = \frac{- ( - 24 ) + 12 3}{2 \cdot 1} : 6 (2 + 3)

x = \frac{- ( - 24 ) - 12 3}{2 \cdot 1} : 6 (2 - 3)

The solutions to the quadratic equation are:

x = 6 (2 + 3), x = 6 (2 - 3)

12 w^{2} - 13 w + 3 = 0

0 = - 5 x^{2} + 225

(4 x - 5) (x + 2) = 4 x + 1

2 x (x + 3) = x^{2} + 3 x + 70

- x^{2} + 9 x - 3

What are the solutions to the equation x^2-24x+36=0 ?
The solutions to the equation x^2-24x+36=0 are x=6(2+sqrt(3)),x=6(2-sqrt(3))
Find the zeros of x^2-24x+36=0
The zeros of x^2-24x+36=0 are x=6(2+sqrt(3)),x=6(2-sqrt(3))