What are the solutions to the equation solvefor x,x^2+2xy+y^2=64 ?

The solutions to the equation solvefor x,x^2+2xy+y^2=64 are x=-y+8,x=-y-8

Find the zeros of solvefor x,x^2+2xy+y^2=64

The zeros of solvefor x,x^2+2xy+y^2=64 are x=-y+8,x=-y-8

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solve for

x, x^{2} + 2 x y + y^{2} = 64

x = - y + 8, x = - y - 8

Solution steps

x^{2} + 2 x y + y^{2} = 64

Move

64

to the left side

x^{2} + 2 x y + y^{2} - 64 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 2 y x + y^{2} - 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 y \pm ( 2 y ) ^{2} - 4 \cdot 1 \cdot ( y ^{2} - 64 )}{2 \cdot 1}

(2 y)^{2} - 4 \cdot 1 \cdot (y^{2} - 64) = 16

x_{1, 2} = \frac{- 2 y \pm 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 y + 16}{2 \cdot 1}, x_{2} = \frac{- 2 y - 16}{2 \cdot 1}

x = \frac{- 2 y + 16}{2 \cdot 1} : - y + 8

x = \frac{- 2 y - 16}{2 \cdot 1} : - y - 8

The solutions to the quadratic equation are:

x = - y + 8, x = - y - 8

x^{2} + 5 = 5 \frac{1}{16}

x^{2} + \frac{x}{2} + 1 = 0

x^{2} - 5 x + 6 = 20

2 x^{2} + x + 12 = 0

(m - 5) x^{2} - 24 x + 9 = 0

What are the solutions to the equation solvefor x,x^2+2xy+y^2=64 ?
The solutions to the equation solvefor x,x^2+2xy+y^2=64 are x=-y+8,x=-y-8
Find the zeros of solvefor x,x^2+2xy+y^2=64
The zeros of solvefor x,x^2+2xy+y^2=64 are x=-y+8,x=-y-8