What are the solutions to the equation 2t(t+1)=7 ?

The solutions to the equation 2t(t+1)=7 are t=(-1+sqrt(15))/2 ,t=-(1+sqrt(15))/2

Find the zeros of 2t(t+1)=7

The zeros of 2t(t+1)=7 are t=(-1+sqrt(15))/2 ,t=-(1+sqrt(15))/2

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2 t (t + 1) = 7

t = \frac{- 1 + 15}{2}, t = - \frac{1 + 15}{2}

Decimal Notation

t = 1.43649 \dots, t = - 2.43649 \dots

Solution steps

2 t (t + 1) = 7

Expand

2 t (t + 1) : 2 t^{2} + 2 t

2 t^{2} + 2 t = 7

Move

7

to the left side

2 t^{2} + 2 t - 7 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 ( - 7 )}{2 \cdot 2}

2^{2} - 4 \cdot 2 (- 7) = 215

t_{1, 2} = \frac{- 2 \pm 2 15}{2 \cdot 2}

Separate the solutions

t_{1} = \frac{- 2 + 2 15}{2 \cdot 2}, t_{2} = \frac{- 2 - 2 15}{2 \cdot 2}

t = \frac{- 2 + 2 15}{2 \cdot 2} : \frac{- 1 + 15}{2}

t = \frac{- 2 - 2 15}{2 \cdot 2} : - \frac{1 + 15}{2}

The solutions to the quadratic equation are:

t = \frac{- 1 + 15}{2}, t = - \frac{1 + 15}{2}

r, y = 4 π r^{2}

x^{2} - 3 \cdot (- 10) = 0

v, F = \frac{d M v ^{2}}{r}

2 (y^{2} + 3 y) = 9

3 x^{2} - 110 x + 900 = 0

What are the solutions to the equation 2t(t+1)=7 ?
The solutions to the equation 2t(t+1)=7 are t=(-1+sqrt(15))/2 ,t=-(1+sqrt(15))/2
Find the zeros of 2t(t+1)=7
The zeros of 2t(t+1)=7 are t=(-1+sqrt(15))/2 ,t=-(1+sqrt(15))/2