What are the solutions to the equation 2x^2+7=31 ?

The solutions to the equation 2x^2+7=31 are x=2sqrt(3),x=-2sqrt(3)

Find the zeros of 2x^2+7=31

The zeros of 2x^2+7=31 are x=2sqrt(3),x=-2sqrt(3)

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2 x^{2} + 7 = 31

x = 23, x = - 23

Decimal Notation

x = 3.46410 \dots, x = - 3.46410 \dots

Solution steps

2 x^{2} + 7 = 31

Move

7

to the right side

2 x^{2} = 24

Divide both sides by

2

x^{2} = 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 12, x = - 12

12 = 23

- 12 = - 23

x = 23, x = - 23

(2 x + 4) (x - 2) = (x + 4) (x + 2)

(2 x - 1)^{2} - 225 = 0

3 x^{2} - 4 x = 3

x^{2} + 4 = 6 x - 5

49 x^{2} - 21 x + 2 = 0

What are the solutions to the equation 2x^2+7=31 ?
The solutions to the equation 2x^2+7=31 are x=2sqrt(3),x=-2sqrt(3)
Find the zeros of 2x^2+7=31
The zeros of 2x^2+7=31 are x=2sqrt(3),x=-2sqrt(3)