What are the solutions to the equation 3n^2+12n-15=0 ?

The solutions to the equation 3n^2+12n-15=0 are n=1,n=-5

Find the zeros of 3n^2+12n-15=0

The zeros of 3n^2+12n-15=0 are n=1,n=-5

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3 n^{2} + 12 n - 15 = 0

n = 1, n = - 5

Solution steps

3 n^{2} + 12 n - 15 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 3 ( - 15 )}{2 \cdot 3}

1 2^{2} - 4 \cdot 3 (- 15) = 18

n_{1, 2} = \frac{- 12 \pm 18}{2 \cdot 3}

Separate the solutions

n_{1} = \frac{- 12 + 18}{2 \cdot 3}, n_{2} = \frac{- 12 - 18}{2 \cdot 3}

n = \frac{- 12 + 18}{2 \cdot 3} : 1

n = \frac{- 12 - 18}{2 \cdot 3} : - 5

The solutions to the quadratic equation are:

n = 1, n = - 5

2 g^{2} = 4 (17 + 8) + g^{2}

x = 0.25 x^{2} - 14.5 x + 200

y, x = y^{2} - 8 y + 3

0.05 x^{2} - 0.08 x = 0

- 2 x^{2} + 100 x

What are the solutions to the equation 3n^2+12n-15=0 ?
The solutions to the equation 3n^2+12n-15=0 are n=1,n=-5
Find the zeros of 3n^2+12n-15=0
The zeros of 3n^2+12n-15=0 are n=1,n=-5