What are the solutions to the equation x^2+22x-5=0 ?

The solutions to the equation x^2+22x-5=0 are x=-11+3sqrt(14),x=-11-3sqrt(14)

Find the zeros of x^2+22x-5=0

The zeros of x^2+22x-5=0 are x=-11+3sqrt(14),x=-11-3sqrt(14)

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x^{2} + 22 x - 5 = 0

x = - 11 + 314, x = - 11 - 314

Solution steps

x^{2} + 22 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

2 2^{2} - 4 \cdot 1 \cdot (- 5) = 614

x_{1, 2} = \frac{- 22 \pm 6 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 22 + 6 14}{2 \cdot 1}, x_{2} = \frac{- 22 - 6 14}{2 \cdot 1}

x = \frac{- 22 + 6 14}{2 \cdot 1} : - 11 + 314

x = \frac{- 22 - 6 14}{2 \cdot 1} : - 11 - 314

The solutions to the quadratic equation are:

x = - 11 + 314, x = - 11 - 314

x^{2} - 126 = 2 x + 1

60 = 50 + 20 \cdot t - 5 \cdot t^{2}

x^{2} + 32 x

x^{2} + 4 x = 98

x^{2} + 21 = 142

What are the solutions to the equation x^2+22x-5=0 ?
The solutions to the equation x^2+22x-5=0 are x=-11+3sqrt(14),x=-11-3sqrt(14)
Find the zeros of x^2+22x-5=0
The zeros of x^2+22x-5=0 are x=-11+3sqrt(14),x=-11-3sqrt(14)