What are the solutions to the equation -2x^2-x+7=0 ?

The solutions to the equation -2x^2-x+7=0 are x=-(1+sqrt(57))/4 ,x=(sqrt(57)-1)/4

Find the zeros of -2x^2-x+7=0

The zeros of -2x^2-x+7=0 are x=-(1+sqrt(57))/4 ,x=(sqrt(57)-1)/4

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- 2 x^{2} - x + 7 = 0

x = - \frac{1 + 57}{4}, x = \frac{57 - 1}{4}

Solution steps

- 2 x^{2} - x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 2 ) \cdot 7}{2 ( - 2 )}

(- 1)^{2} - 4 (- 2) \cdot 7 = 57

x_{1, 2} = \frac{- ( - 1 ) \pm 57}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 57}{2 ( - 2 )}, x_{2} = \frac{- ( - 1 ) - 57}{2 ( - 2 )}

x = \frac{- ( - 1 ) + 57}{2 ( - 2 )} : - \frac{1 + 57}{4}

x = \frac{- ( - 1 ) - 57}{2 ( - 2 )} : \frac{57 - 1}{4}

The solutions to the quadratic equation are:

x = - \frac{1 + 57}{4}, x = \frac{57 - 1}{4}

3 x^{2} = 2 - 5 x

4 x^{2} - 10 x - 4 = 0

n^{2} - 10 = 26

y^{2} - 2 y - 48 = 0

(4 x - 1)^{2} + 8 x = 4 x + 1

What are the solutions to the equation -2x^2-x+7=0 ?
The solutions to the equation -2x^2-x+7=0 are x=-(1+sqrt(57))/4 ,x=(sqrt(57)-1)/4
Find the zeros of -2x^2-x+7=0
The zeros of -2x^2-x+7=0 are x=-(1+sqrt(57))/4 ,x=(sqrt(57)-1)/4