What are the solutions to the equation 12x^2-4x+7=0 ?

The solutions to the equation 12x^2-4x+7=0 are x= 1/6+i(sqrt(5))/3 ,x= 1/6-i(sqrt(5))/3

Find the zeros of 12x^2-4x+7=0

The zeros of 12x^2-4x+7=0 are x= 1/6+i(sqrt(5))/3 ,x= 1/6-i(sqrt(5))/3

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12 x^{2} - 4 x + 7 = 0

x = \frac{1}{6} + i \frac{5}{3}, x = \frac{1}{6} - i \frac{5}{3}

Solution steps

12 x^{2} - 4 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 12 \cdot 7}{2 \cdot 12}

Simplify

(- 4)^{2} - 4 \cdot 12 \cdot 7 : 85 i

x_{1, 2} = \frac{- ( - 4 ) \pm 8 5 i}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8 5 i}{2 \cdot 12}, x_{2} = \frac{- ( - 4 ) - 8 5 i}{2 \cdot 12}

x = \frac{- ( - 4 ) + 8 5 i}{2 \cdot 12} : \frac{1}{6} + i \frac{5}{3}

x = \frac{- ( - 4 ) - 8 5 i}{2 \cdot 12} : \frac{1}{6} - i \frac{5}{3}

The solutions to the quadratic equation are:

x = \frac{1}{6} + i \frac{5}{3}, x = \frac{1}{6} - i \frac{5}{3}

2 (x + 8)^{2} - 3 = 97

(\frac{3 a}{8})^{2} + a = 52

4 v^{2} + 6 v + 1 = 0

(5 x + 3)^{2} = 8

6 x^{2} - 19 x - 10 = 0

What are the solutions to the equation 12x^2-4x+7=0 ?
The solutions to the equation 12x^2-4x+7=0 are x= 1/6+i(sqrt(5))/3 ,x= 1/6-i(sqrt(5))/3
Find the zeros of 12x^2-4x+7=0
The zeros of 12x^2-4x+7=0 are x= 1/6+i(sqrt(5))/3 ,x= 1/6-i(sqrt(5))/3