What are the solutions to the equation 2x(x+4)=42 ?

The solutions to the equation 2x(x+4)=42 are x=3,x=-7

Find the zeros of 2x(x+4)=42

The zeros of 2x(x+4)=42 are x=3,x=-7

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2 x (x + 4) = 42

x = 3, x = - 7

Solution steps

2 x (x + 4) = 42

Expand

2 x (x + 4) : 2 x^{2} + 8 x

2 x^{2} + 8 x = 42

Move

42

to the left side

2 x^{2} + 8 x - 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 ( - 42 )}{2 \cdot 2}

8^{2} - 4 \cdot 2 (- 42) = 20

x_{1, 2} = \frac{- 8 \pm 20}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 8 + 20}{2 \cdot 2}, x_{2} = \frac{- 8 - 20}{2 \cdot 2}

x = \frac{- 8 + 20}{2 \cdot 2} : 3

x = \frac{- 8 - 20}{2 \cdot 2} : - 7

The solutions to the quadratic equation are:

x = 3, x = - 7

Q^{2} - 10599.74 Q + 375000 = 0

2 t^{2} + 40 t + 34 = 0

15 x^{2} - 23 x + 4 = 0

2 x^{2} + 20 x

0.15 y (y - 0.2) = 2 - 0.5 (1 - y)

What are the solutions to the equation 2x(x+4)=42 ?
The solutions to the equation 2x(x+4)=42 are x=3,x=-7
Find the zeros of 2x(x+4)=42
The zeros of 2x(x+4)=42 are x=3,x=-7