What are the solutions to the equation (4x-3)(5x-7)=0 ?

The solutions to the equation (4x-3)(5x-7)=0 are x= 3/4 ,x= 7/5

Find the zeros of (4x-3)(5x-7)=0

The zeros of (4x-3)(5x-7)=0 are x= 3/4 ,x= 7/5

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(4 x - 3) (5 x - 7) = 0

x = \frac{3}{4}, x = \frac{7}{5}

Solution steps

(4 x - 3) (5 x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x - 3 = 0 or 5 x - 7 = 0

Solve

4 x - 3 = 0 : x = \frac{3}{4}

Solve

5 x - 7 = 0 : x = \frac{7}{5}

The solutions to the quadratic equation are:

x = \frac{3}{4}, x = \frac{7}{5}

x, - 3 = 4 x^{2} - x - 3

- 5 n^{2} + 2 n - 7 = 0

2 x^{2} + 7 x = 3

4 + 16.3 t - 4.9 t^{2} = 0

(x - 20)^{2} = 81

What are the solutions to the equation (4x-3)(5x-7)=0 ?
The solutions to the equation (4x-3)(5x-7)=0 are x= 3/4 ,x= 7/5
Find the zeros of (4x-3)(5x-7)=0
The zeros of (4x-3)(5x-7)=0 are x= 3/4 ,x= 7/5