What are the solutions to the equation 4x^2-12x=0 ?

The solutions to the equation 4x^2-12x=0 are x=3,x=0

Find the zeros of 4x^2-12x=0

The zeros of 4x^2-12x=0 are x=3,x=0

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4 x^{2} - 12 x = 0

x = 3, x = 0

Solution steps

4 x^{2} - 12 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 0 = 12

x_{1, 2} = \frac{- ( - 12 ) \pm 12}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 12}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 12}{2 \cdot 4}

x = \frac{- ( - 12 ) + 12}{2 \cdot 4} : 3

x = \frac{- ( - 12 ) - 12}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

x = 3, x = 0

5 x + 2 < 4 x - 4

5 x^{2} - 25 x = 0

4 x y^{2} (3 y - x) - 2 x^{2} (x - 3 y)^{2}

(\frac{m ^{- 2} n}{2 m n ^{3}})^{2}

2 - [- 2 (x + 1) - \frac{x - 3}{2}] = \frac{2 x}{3} - \frac{5 x - 3}{12} + 3 x

What are the solutions to the equation 4x^2-12x=0 ?
The solutions to the equation 4x^2-12x=0 are x=3,x=0
Find the zeros of 4x^2-12x=0
The zeros of 4x^2-12x=0 are x=3,x=0