What are the solutions to the equation 1=(x-4)^2 ?

The solutions to the equation 1=(x-4)^2 are x=5,x=3

Find the zeros of 1=(x-4)^2

The zeros of 1=(x-4)^2 are x=5,x=3

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1 = (x - 4)^{2}

x = 5, x = 3

Solution steps

1 = (x - 4)^{2}

Switch sides

(x - 4)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 1 : x = 5

Solve

x - 4 = - 1 : x = 3

The solutions to the quadratic equation are:

x = 5, x = 3

7.757 = π \cdot r^{2} \cdot 126

2 c^{2} - c - 15 = 0

2 (3 x^{2} - 2 x + 2) = 15 \cdot x^{2}

5 n^{2} = - 8 n - 8

3 z^{2} - 27 = 0

What are the solutions to the equation 1=(x-4)^2 ?
The solutions to the equation 1=(x-4)^2 are x=5,x=3
Find the zeros of 1=(x-4)^2
The zeros of 1=(x-4)^2 are x=5,x=3