What are the solutions to the equation solvefor x,2x^2-3x-5=0 ?

The solutions to the equation solvefor x,2x^2-3x-5=0 are x= 5/2 ,x=-1

Find the zeros of solvefor x,2x^2-3x-5=0

The zeros of solvefor x,2x^2-3x-5=0 are x= 5/2 ,x=-1

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x, 2 x^{2} - 3 x - 5 = 0

x = \frac{5}{2}, x = - 1

Solution steps

2 x^{2} - 3 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 5) = 7

x_{1, 2} = \frac{- ( - 3 ) \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 7}{2 \cdot 2}, x_{2} = \frac{- ( - 3 ) - 7}{2 \cdot 2}

x = \frac{- ( - 3 ) + 7}{2 \cdot 2} : \frac{5}{2}

x = \frac{- ( - 3 ) - 7}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - 1

x^{2} + 6 x + 107 = 0

\frac{70 - 2 x ^{2}}{a} = 5

4 x^{2} + 11 x + 3 = 0

x^{2} = \frac{25}{289}

2 x^{2} - 20 x = - 49

What are the solutions to the equation solvefor x,2x^2-3x-5=0 ?
The solutions to the equation solvefor x,2x^2-3x-5=0 are x= 5/2 ,x=-1
Find the zeros of solvefor x,2x^2-3x-5=0
The zeros of solvefor x,2x^2-3x-5=0 are x= 5/2 ,x=-1