What are the solutions to the equation x^2+8x+64=0 ?

The solutions to the equation x^2+8x+64=0 are x=-4+4sqrt(3)i,x=-4-4sqrt(3)i

Find the zeros of x^2+8x+64=0

The zeros of x^2+8x+64=0 are x=-4+4sqrt(3)i,x=-4-4sqrt(3)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 8 x + 64 = 0

x = - 4 + 43 i, x = - 4 - 43 i

Solution steps

x^{2} + 8 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 64}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 64 : 83 i

x_{1, 2} = \frac{- 8 \pm 8 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 8 3 i}{2 \cdot 1}, x_{2} = \frac{- 8 - 8 3 i}{2 \cdot 1}

x = \frac{- 8 + 8 3 i}{2 \cdot 1} : - 4 + 43 i

x = \frac{- 8 - 8 3 i}{2 \cdot 1} : - 4 - 43 i

The solutions to the quadratic equation are:

x = - 4 + 43 i, x = - 4 - 43 i

x^{2} - 4 x - 32 \leq 0

2 + 3 n = 11

lo g_{e} (4)

\frac{x}{4} + \frac{x}{10} = \frac{3}{5}

9 x^{2} - 15 x = 0

What are the solutions to the equation x^2+8x+64=0 ?
The solutions to the equation x^2+8x+64=0 are x=-4+4sqrt(3)i,x=-4-4sqrt(3)i
Find the zeros of x^2+8x+64=0
The zeros of x^2+8x+64=0 are x=-4+4sqrt(3)i,x=-4-4sqrt(3)i