What are the solutions to the equation 2x^2+5x=25 ?

The solutions to the equation 2x^2+5x=25 are x= 5/2 ,x=-5

Find the zeros of 2x^2+5x=25

The zeros of 2x^2+5x=25 are x= 5/2 ,x=-5

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2 x^{2} + 5 x = 25

x = \frac{5}{2}, x = - 5

Decimal Notation

x = 2.5, x = - 5

Solution steps

2 x^{2} + 5 x = 25

Move

25

to the left side

2 x^{2} + 5 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 25 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 25) = 15

x_{1, 2} = \frac{- 5 \pm 15}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 15}{2 \cdot 2}, x_{2} = \frac{- 5 - 15}{2 \cdot 2}

x = \frac{- 5 + 15}{2 \cdot 2} : \frac{5}{2}

x = \frac{- 5 - 15}{2 \cdot 2} : - 5

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - 5

x^{2} = 2 x + 7

(x + 3) (x - 1) = - 3 x + 4

- x^{2} + 2 x - 15 = 0

x^{2} + x - 8

y, x = y^{2} - 3

What are the solutions to the equation 2x^2+5x=25 ?
The solutions to the equation 2x^2+5x=25 are x= 5/2 ,x=-5
Find the zeros of 2x^2+5x=25
The zeros of 2x^2+5x=25 are x= 5/2 ,x=-5