What are the solutions to the equation (y+6)^2-72=0 ?

The solutions to the equation (y+6)^2-72=0 are y=6sqrt(2)-6,y=-6sqrt(2)-6

Find the zeros of (y+6)^2-72=0

The zeros of (y+6)^2-72=0 are y=6sqrt(2)-6,y=-6sqrt(2)-6

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(y + 6)^{2} - 72 = 0

y = 62 - 6, y = - 62 - 6

Decimal Notation

y = 2.48528 \dots, y = - 14.48528 \dots

Solution steps

(y + 6)^{2} - 72 = 0

Move

72

to the right side

(y + 6)^{2} = 72

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y + 6 = 72 : y = 62 - 6

Solve

y + 6 = - 72 : y = - 62 - 6

The solutions to the quadratic equation are:

y = 62 - 6, y = - 62 - 6

x^{2} + 18 x + 85 = 0

3 x^{2} = 2 x + 2

z, 3 z^{2} + A z + B = 0

3 x^{2} - 5 x = 8

- 3 x^{2} + 21 x = 0

What are the solutions to the equation (y+6)^2-72=0 ?
The solutions to the equation (y+6)^2-72=0 are y=6sqrt(2)-6,y=-6sqrt(2)-6
Find the zeros of (y+6)^2-72=0
The zeros of (y+6)^2-72=0 are y=6sqrt(2)-6,y=-6sqrt(2)-6