What are the solutions to the equation -6x^2+2x-1=0 ?

The solutions to the equation -6x^2+2x-1=0 are x= 1/6-i(sqrt(5))/6 ,x= 1/6+i(sqrt(5))/6

Find the zeros of -6x^2+2x-1=0

The zeros of -6x^2+2x-1=0 are x= 1/6-i(sqrt(5))/6 ,x= 1/6+i(sqrt(5))/6

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- 6 x^{2} + 2 x - 1 = 0

x = \frac{1}{6} - i \frac{5}{6}, x = \frac{1}{6} + i \frac{5}{6}

Solution steps

- 6 x^{2} + 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 6 ) ( - 1 )}{2 ( - 6 )}

Simplify

2^{2} - 4 (- 6) (- 1) : 25 i

x_{1, 2} = \frac{- 2 \pm 2 5 i}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 5 i}{2 ( - 6 )}, x_{2} = \frac{- 2 - 2 5 i}{2 ( - 6 )}

x = \frac{- 2 + 2 5 i}{2 ( - 6 )} : \frac{1}{6} - i \frac{5}{6}

x = \frac{- 2 - 2 5 i}{2 ( - 6 )} : \frac{1}{6} + i \frac{5}{6}

The solutions to the quadratic equation are:

x = \frac{1}{6} - i \frac{5}{6}, x = \frac{1}{6} + i \frac{5}{6}

q^{2} + 11 q

2 x^{2} - 6 x - 11 = 0

x + 2 = (x - 5) (x + 2)

2 x^{2} + 5 x = - 6

0 = 2 x^{2} - 3 x + 1

What are the solutions to the equation -6x^2+2x-1=0 ?
The solutions to the equation -6x^2+2x-1=0 are x= 1/6-i(sqrt(5))/6 ,x= 1/6+i(sqrt(5))/6
Find the zeros of -6x^2+2x-1=0
The zeros of -6x^2+2x-1=0 are x= 1/6-i(sqrt(5))/6 ,x= 1/6+i(sqrt(5))/6