What are the solutions to the equation 12x^2+1=0 ?

The solutions to the equation 12x^2+1=0 are x= 1/(2sqrt(3))i,x=-1/(2sqrt(3))i

Find the zeros of 12x^2+1=0

The zeros of 12x^2+1=0 are x= 1/(2sqrt(3))i,x=-1/(2sqrt(3))i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

12 x^{2} + 1 = 0

x = \frac{1}{2 3} i, x = - \frac{1}{2 3} i

Solution steps

12 x^{2} + 1 = 0

Move

1

to the right side

12 x^{2} = - 1

Divide both sides by

12

x^{2} = - \frac{1}{12}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{12}, x = - - \frac{1}{12}

- \frac{1}{12} = \frac{1}{2 3} i

- - \frac{1}{12} = - \frac{1}{2 3} i

x = \frac{1}{2 3} i, x = - \frac{1}{2 3} i

x, x^{2} - 6 x = 0

x^{2} = 7 x - 13

x^{2} + 9 (0)^{2} = 0

2 x^{2} - 7 x + 6 = 0

6596 x^{2} + 924 x - 2856 = 0

What are the solutions to the equation 12x^2+1=0 ?
The solutions to the equation 12x^2+1=0 are x= 1/(2sqrt(3))i,x=-1/(2sqrt(3))i
Find the zeros of 12x^2+1=0
The zeros of 12x^2+1=0 are x= 1/(2sqrt(3))i,x=-1/(2sqrt(3))i