What are the solutions to the equation 7x^2+42x-112=0 ?

The solutions to the equation 7x^2+42x-112=0 are x=2,x=-8

Find the zeros of 7x^2+42x-112=0

The zeros of 7x^2+42x-112=0 are x=2,x=-8

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7 x^{2} + 42 x - 112 = 0

x = 2, x = - 8

Solution steps

7 x^{2} + 42 x - 112 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 42 \pm 4 2 ^{2} - 4 \cdot 7 ( - 112 )}{2 \cdot 7}

4 2^{2} - 4 \cdot 7 (- 112) = 70

x_{1, 2} = \frac{- 42 \pm 70}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 42 + 70}{2 \cdot 7}, x_{2} = \frac{- 42 - 70}{2 \cdot 7}

x = \frac{- 42 + 70}{2 \cdot 7} : 2

x = \frac{- 42 - 70}{2 \cdot 7} : - 8

The solutions to the quadratic equation are:

x = 2, x = - 8

3 x^{2} - 12 = 0

m^{2} = 18

x, 4 x^{2} - 3 x y^{2} = C

b^{2} - 5 b - 6 = 0

4 z + z^{2} + 12 = 0

What are the solutions to the equation 7x^2+42x-112=0 ?
The solutions to the equation 7x^2+42x-112=0 are x=2,x=-8
Find the zeros of 7x^2+42x-112=0
The zeros of 7x^2+42x-112=0 are x=2,x=-8