What are the solutions to the equation p^2+8p+21=10 ?

The solutions to the equation p^2+8p+21=10 are p=-4+sqrt(5),p=-4-sqrt(5)

Find the zeros of p^2+8p+21=10

The zeros of p^2+8p+21=10 are p=-4+sqrt(5),p=-4-sqrt(5)

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p^{2} + 8 p + 21 = 10

p = - 4 + 5, p = - 4 - 5

Decimal Notation

p = - 1.76393 \dots, p = - 6.23606 \dots

Solution steps

p^{2} + 8 p + 21 = 10

Move

10

to the left side

p^{2} + 8 p + 11 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 11}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 11 = 25

p_{1, 2} = \frac{- 8 \pm 2 5}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 8 + 2 5}{2 \cdot 1}, p_{2} = \frac{- 8 - 2 5}{2 \cdot 1}

p = \frac{- 8 + 2 5}{2 \cdot 1} : - 4 + 5

p = \frac{- 8 - 2 5}{2 \cdot 1} : - 4 - 5

The solutions to the quadratic equation are:

p = - 4 + 5, p = - 4 - 5

x^{2} - 2 \cdot (- 3) = 0

3 x^{2} + x = 4 + 3 x

2 a^{2} - 50 = 0

x^{2} - 16 = 33

g^{2} + 8 g + 7 = 0

What are the solutions to the equation p^2+8p+21=10 ?
The solutions to the equation p^2+8p+21=10 are p=-4+sqrt(5),p=-4-sqrt(5)
Find the zeros of p^2+8p+21=10
The zeros of p^2+8p+21=10 are p=-4+sqrt(5),p=-4-sqrt(5)