What are the solutions to the equation 5a^2-11a=45 ?

The solutions to the equation 5a^2-11a=45 are a=(11+sqrt(1021))/(10),a=(11-sqrt(1021))/(10)

Find the zeros of 5a^2-11a=45

The zeros of 5a^2-11a=45 are a=(11+sqrt(1021))/(10),a=(11-sqrt(1021))/(10)

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5 a^{2} - 11 a = 45

a = \frac{11 + 1021}{10}, a = \frac{11 - 1021}{10}

Decimal Notation

a = 4.29530 \dots, a = - 2.09530 \dots

Solution steps

5 a^{2} - 11 a = 45

Move

45

to the left side

5 a^{2} - 11 a - 45 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 5 ( - 45 )}{2 \cdot 5}

(- 11)^{2} - 4 \cdot 5 (- 45) = 1021

a_{1, 2} = \frac{- ( - 11 ) \pm 1021}{2 \cdot 5}

Separate the solutions

a_{1} = \frac{- ( - 11 ) + 1021}{2 \cdot 5}, a_{2} = \frac{- ( - 11 ) - 1021}{2 \cdot 5}

a = \frac{- ( - 11 ) + 1021}{2 \cdot 5} : \frac{11 + 1021}{10}

a = \frac{- ( - 11 ) - 1021}{2 \cdot 5} : \frac{11 - 1021}{10}

The solutions to the quadratic equation are:

a = \frac{11 + 1021}{10}, a = \frac{11 - 1021}{10}

x, x^{2} - 4 x - 16 = - 4 x

w^{2} - w + 1 = 0

n^{2} = - 7 n - 10

(x + 4) (x + 7) = 0

x^{2} + 4 x - 35 = 0

What are the solutions to the equation 5a^2-11a=45 ?
The solutions to the equation 5a^2-11a=45 are a=(11+sqrt(1021))/(10),a=(11-sqrt(1021))/(10)
Find the zeros of 5a^2-11a=45
The zeros of 5a^2-11a=45 are a=(11+sqrt(1021))/(10),a=(11-sqrt(1021))/(10)