What are the solutions to the equation 3x^2-14x-13=2x^2 ?

The solutions to the equation 3x^2-14x-13=2x^2 are x=7+sqrt(62),x=7-sqrt(62)

Find the zeros of 3x^2-14x-13=2x^2

The zeros of 3x^2-14x-13=2x^2 are x=7+sqrt(62),x=7-sqrt(62)

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3 x^{2} - 14 x - 13 = 2 x^{2}

x = 7 + 62, x = 7 - 62

Decimal Notation

x = 14.87400 \dots, x = - 0.87400 \dots

Solution steps

3 x^{2} - 14 x - 13 = 2 x^{2}

Move

2 x^{2}

to the left side

x^{2} - 14 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot ( - 13 )}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot (- 13) = 262

x_{1, 2} = \frac{- ( - 14 ) \pm 2 62}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 62}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 2 62}{2 \cdot 1}

x = \frac{- ( - 14 ) + 2 62}{2 \cdot 1} : 7 + 62

x = \frac{- ( - 14 ) - 2 62}{2 \cdot 1} : 7 - 62

The solutions to the quadratic equation are:

x = 7 + 62, x = 7 - 62

x^{2} - 3 x = 3 x^{2} - 5 x - 24

x^{2} + (x - 8)^{2} - 10 = (3 x - 1) (x - 5)

3 x^{2} - 100 x + 750 = 0

(x + 4) (x + 6) = 8

2 p^{2} + 8 p = - 3

What are the solutions to the equation 3x^2-14x-13=2x^2 ?
The solutions to the equation 3x^2-14x-13=2x^2 are x=7+sqrt(62),x=7-sqrt(62)
Find the zeros of 3x^2-14x-13=2x^2
The zeros of 3x^2-14x-13=2x^2 are x=7+sqrt(62),x=7-sqrt(62)