What are the solutions to the equation (2x-3)(x-2)=15 ?

The solutions to the equation (2x-3)(x-2)=15 are x= 9/2 ,x=-1

Find the zeros of (2x-3)(x-2)=15

The zeros of (2x-3)(x-2)=15 are x= 9/2 ,x=-1

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(2 x - 3) (x - 2) = 15

x = \frac{9}{2}, x = - 1

Decimal Notation

x = 4.5, x = - 1

Solution steps

(2 x - 3) (x - 2) = 15

Expand

(2 x - 3) (x - 2) : 2 x^{2} - 7 x + 6

2 x^{2} - 7 x + 6 = 15

Move

15

to the left side

2 x^{2} - 7 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 9 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 9) = 11

x_{1, 2} = \frac{- ( - 7 ) \pm 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 11}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 11}{2 \cdot 2}

x = \frac{- ( - 7 ) + 11}{2 \cdot 2} : \frac{9}{2}

x = \frac{- ( - 7 ) - 11}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = \frac{9}{2}, x = - 1

(9 x - 4 + 2)^{2} = 3

1296 b^{4} - d^{4}

- 3 (p - 7) > 21

x (3 x - 8) = 0

8^{7} \cdot \frac{8 ^{3}}{8 ^{6}}

What are the solutions to the equation (2x-3)(x-2)=15 ?
The solutions to the equation (2x-3)(x-2)=15 are x= 9/2 ,x=-1
Find the zeros of (2x-3)(x-2)=15
The zeros of (2x-3)(x-2)=15 are x= 9/2 ,x=-1