What are the solutions to the equation (m+6)(m-3)=-18 ?

The solutions to the equation (m+6)(m-3)=-18 are m=0,m=-3

Find the zeros of (m+6)(m-3)=-18

The zeros of (m+6)(m-3)=-18 are m=0,m=-3

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(m + 6) (m - 3) = - 18

m = 0, m = - 3

Solution steps

(m + 6) (m - 3) = - 18

Expand

(m + 6) (m - 3) : m^{2} + 3 m - 18

m^{2} + 3 m - 18 = - 18

Move

18

to the left side

m^{2} + 3 m = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot 0 = 3

m_{1, 2} = \frac{- 3 \pm 3}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 3 + 3}{2 \cdot 1}, m_{2} = \frac{- 3 - 3}{2 \cdot 1}

m = \frac{- 3 + 3}{2 \cdot 1} : 0

m = \frac{- 3 - 3}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

m = 0, m = - 3

- 8 x^{2} - 6 = - x^{2} + 2 x + 1

1.3 x^{2} - 4 x = 3.5

x, C x^{2} + x + y^{2} = 0

x^{2} - 8 x + 16 = - 12

x, f (x + 2) = x^{2} - 3 x + 2

What are the solutions to the equation (m+6)(m-3)=-18 ?
The solutions to the equation (m+6)(m-3)=-18 are m=0,m=-3
Find the zeros of (m+6)(m-3)=-18
The zeros of (m+6)(m-3)=-18 are m=0,m=-3