What are the solutions to the equation completesquare x^2+4x=10 ?

The solutions to the equation completesquare x^2+4x=10 are x=sqrt(14)-2,x=-sqrt(14)-2

Find the zeros of completesquare x^2+4x=10

The zeros of completesquare x^2+4x=10 are x=sqrt(14)-2,x=-sqrt(14)-2

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x^{2} + 4 x = 10

x = 14 - 2, x = - 14 - 2

Decimal Notation

x = 1.74165 \dots, x = - 5.74165 \dots

Solution steps

x^{2} + 4 x = 10

Rewrite in the form

(x + a)^{2} = b

(x + 2)^{2} = 14

For

the solutions are

f (x) = a, - a

Solve

x + 2 = 14 : x = 14 - 2

Solve

x + 2 = - 14 : x = - 14 - 2

The solutions to the quadratic equation are:

x = 14 - 2, x = - 14 - 2

x^{2} + 4 x = 32

2 x^{2} - (x - 1) (x + 1) = 6 - x

3 x^{2} + 1 = 31

x^{2} - 9 x + 18 = 10

0 = 2.5 x^{2} + x - 1.5

What are the solutions to the equation completesquare x^2+4x=10 ?
The solutions to the equation completesquare x^2+4x=10 are x=sqrt(14)-2,x=-sqrt(14)-2
Find the zeros of completesquare x^2+4x=10
The zeros of completesquare x^2+4x=10 are x=sqrt(14)-2,x=-sqrt(14)-2