What are the solutions to the equation 3x^2=4x+7 ?

The solutions to the equation 3x^2=4x+7 are x= 7/3 ,x=-1

Find the zeros of 3x^2=4x+7

The zeros of 3x^2=4x+7 are x= 7/3 ,x=-1

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3 x^{2} = 4 x + 7

x = \frac{7}{3}, x = - 1

Decimal Notation

x = 2.33333 \dots, x = - 1

Solution steps

3 x^{2} = 4 x + 7

Move

7

to the left side

3 x^{2} - 7 = 4 x

Move

4 x

to the left side

3 x^{2} - 7 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - 4 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

(- 4)^{2} - 4 \cdot 3 (- 7) = 10

x_{1, 2} = \frac{- ( - 4 ) \pm 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 10}{2 \cdot 3}, x_{2} = \frac{- ( - 4 ) - 10}{2 \cdot 3}

x = \frac{- ( - 4 ) + 10}{2 \cdot 3} : \frac{7}{3}

x = \frac{- ( - 4 ) - 10}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = \frac{7}{3}, x = - 1

(x - 4)^{2} - 4 = 0

3 x^{2} - 20 x - 100 = 0

x^{2} - 100 = 0

5 x^{2} - 10 x + 11 = 0

2 w^{2} + 5 w - 16 = (w + 2)^{2}

What are the solutions to the equation 3x^2=4x+7 ?
The solutions to the equation 3x^2=4x+7 are x= 7/3 ,x=-1
Find the zeros of 3x^2=4x+7
The zeros of 3x^2=4x+7 are x= 7/3 ,x=-1