What are the solutions to the equation 3x^2-4=-5x ?

The solutions to the equation 3x^2-4=-5x are x=(-5+sqrt(73))/6 ,x=(-5-sqrt(73))/6

Find the zeros of 3x^2-4=-5x

The zeros of 3x^2-4=-5x are x=(-5+sqrt(73))/6 ,x=(-5-sqrt(73))/6

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3 x^{2} - 4 = - 5 x

x = \frac{- 5 + 73}{6}, x = \frac{- 5 - 73}{6}

Decimal Notation

x = 0.59066 \dots, x = - 2.25733 \dots

Solution steps

3 x^{2} - 4 = - 5 x

Move

5 x

to the left side

3 x^{2} - 4 + 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + 5 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

5^{2} - 4 \cdot 3 (- 4) = 73

x_{1, 2} = \frac{- 5 \pm 73}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 5 + 73}{2 \cdot 3}, x_{2} = \frac{- 5 - 73}{2 \cdot 3}

x = \frac{- 5 + 73}{2 \cdot 3} : \frac{- 5 + 73}{6}

x = \frac{- 5 - 73}{2 \cdot 3} : \frac{- 5 - 73}{6}

The solutions to the quadratic equation are:

x = \frac{- 5 + 73}{6}, x = \frac{- 5 - 73}{6}

3 d^{2} - 4 d = 0

3 x^{2} + 2 x - 14 = 0

8 x^{2} + 9 = 0

2 c (2 c + 1) = c (c - 3) - 3

4 x^{2} = 24 - 2 x^{2}

What are the solutions to the equation 3x^2-4=-5x ?
The solutions to the equation 3x^2-4=-5x are x=(-5+sqrt(73))/6 ,x=(-5-sqrt(73))/6
Find the zeros of 3x^2-4=-5x
The zeros of 3x^2-4=-5x are x=(-5+sqrt(73))/6 ,x=(-5-sqrt(73))/6