What are the solutions to the equation m^2-5=4 ?

The solutions to the equation m^2-5=4 are m=3,m=-3

Find the zeros of m^2-5=4

The zeros of m^2-5=4 are m=3,m=-3

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m^{2} - 5 = 4

m = 3, m = - 3

Solution steps

m^{2} - 5 = 4

Move

5

to the right side

m^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = 9, m = - 9

9 = 3

- 9 = - 3

m = 3, m = - 3

x^{2} + 7 = 6

(13 x - 2)^{2} - 3 (13 x - 2) - 10 = 0

4 x^{2} = 12 - b x

- 4 x^{2} + 7 x - 2 = 0

2 (3 x + 1)^{2} - 32 = 0

What are the solutions to the equation m^2-5=4 ?
The solutions to the equation m^2-5=4 are m=3,m=-3
Find the zeros of m^2-5=4
The zeros of m^2-5=4 are m=3,m=-3