What are the solutions to the equation -2s^2+8s-4=0 ?

The solutions to the equation -2s^2+8s-4=0 are s=2-sqrt(2),s=2+sqrt(2)

Find the zeros of -2s^2+8s-4=0

The zeros of -2s^2+8s-4=0 are s=2-sqrt(2),s=2+sqrt(2)

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- 2 s^{2} + 8 s - 4 = 0

s = 2 - 2, s = 2 + 2

Decimal Notation

s = 0.58578 \dots, s = 3.41421 \dots

Solution steps

- 2 s^{2} + 8 s - 4 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 2 ) ( - 4 )}{2 ( - 2 )}

8^{2} - 4 (- 2) (- 4) = 42

s_{1, 2} = \frac{- 8 \pm 4 2}{2 ( - 2 )}

Separate the solutions

s_{1} = \frac{- 8 + 4 2}{2 ( - 2 )}, s_{2} = \frac{- 8 - 4 2}{2 ( - 2 )}

s = \frac{- 8 + 4 2}{2 ( - 2 )} : 2 - 2

s = \frac{- 8 - 4 2}{2 ( - 2 )} : 2 + 2

The solutions to the quadratic equation are:

s = 2 - 2, s = 2 + 2

x, x^{2} - 3 x + 2 = y

x^{2} + 3 = 9

2 x^{2} - 8 x - 5

5 a^{2} - 36 a = 32

x, f = a (x - h)^{2}

What are the solutions to the equation -2s^2+8s-4=0 ?
The solutions to the equation -2s^2+8s-4=0 are s=2-sqrt(2),s=2+sqrt(2)
Find the zeros of -2s^2+8s-4=0
The zeros of -2s^2+8s-4=0 are s=2-sqrt(2),s=2+sqrt(2)