What are the solutions to the equation -2x^2+14x=0 ?

The solutions to the equation -2x^2+14x=0 are x=0,x=7

Find the zeros of -2x^2+14x=0

The zeros of -2x^2+14x=0 are x=0,x=7

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- 2 x^{2} + 14 x = 0

x = 0, x = 7

Solution steps

- 2 x^{2} + 14 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

1 4^{2} - 4 (- 2) \cdot 0 = 14

x_{1, 2} = \frac{- 14 \pm 14}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 14 + 14}{2 ( - 2 )}, x_{2} = \frac{- 14 - 14}{2 ( - 2 )}

x = \frac{- 14 + 14}{2 ( - 2 )} : 0

x = \frac{- 14 - 14}{2 ( - 2 )} : 7

The solutions to the quadratic equation are:

x = 0, x = 7

3 x^{2} - 9 x = 6

x^{2} = 6 x + a

x^{2} - 8 x - 2 = 0

2 x^{2} - 3 x + 21 = a (x - b)^{2} + c

0.000015 (x + 100)^{2} = 0.225375

What are the solutions to the equation -2x^2+14x=0 ?
The solutions to the equation -2x^2+14x=0 are x=0,x=7
Find the zeros of -2x^2+14x=0
The zeros of -2x^2+14x=0 are x=0,x=7