What are the solutions to the equation 6x=-15x^2+3 ?

The solutions to the equation 6x=-15x^2+3 are x=-(1+sqrt(6))/5 ,x=(sqrt(6)-1)/5

Find the zeros of 6x=-15x^2+3

The zeros of 6x=-15x^2+3 are x=-(1+sqrt(6))/5 ,x=(sqrt(6)-1)/5

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6 x = - 15 x^{2} + 3

x = - \frac{1 + 6}{5}, x = \frac{6 - 1}{5}

Decimal Notation

x = - 0.68989 \dots, x = 0.28989 \dots

Solution steps

6 x = - 15 x^{2} + 3

Switch sides

- 15 x^{2} + 3 = 6 x

Move

6 x

to the left side

- 15 x^{2} + 3 - 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 15 x^{2} - 6 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 15 ) \cdot 3}{2 ( - 15 )}

(- 6)^{2} - 4 (- 15) \cdot 3 = 66

x_{1, 2} = \frac{- ( - 6 ) \pm 6 6}{2 ( - 15 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 6}{2 ( - 15 )}, x_{2} = \frac{- ( - 6 ) - 6 6}{2 ( - 15 )}

x = \frac{- ( - 6 ) + 6 6}{2 ( - 15 )} : - \frac{1 + 6}{5}

x = \frac{- ( - 6 ) - 6 6}{2 ( - 15 )} : \frac{6 - 1}{5}

The solutions to the quadratic equation are:

x = - \frac{1 + 6}{5}, x = \frac{6 - 1}{5}

3 x^{2} - 1 = 2 (16 - x)

x^{2} - 30 = 3 x - 2

s^{2} L - s - 2 + 5 (L) + 4 L = 4

x, z^{2} + 4 x^{2} = 16

x, x^{2} y - 2 = cy - x y

What are the solutions to the equation 6x=-15x^2+3 ?
The solutions to the equation 6x=-15x^2+3 are x=-(1+sqrt(6))/5 ,x=(sqrt(6)-1)/5
Find the zeros of 6x=-15x^2+3
The zeros of 6x=-15x^2+3 are x=-(1+sqrt(6))/5 ,x=(sqrt(6)-1)/5