What are the solutions to the equation (x-6)(x-10)=-4 ?

The solutions to the equation (x-6)(x-10)=-4 are x=8

Find the zeros of (x-6)(x-10)=-4

The zeros of (x-6)(x-10)=-4 are x=8

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(x - 6) (x - 10) = - 4

x = 8

Solution steps

(x - 6) (x - 10) = - 4

Expand

(x - 6) (x - 10) : x^{2} - 16 x + 60

x^{2} - 16 x + 60 = - 4

Move

4

to the left side

x^{2} - 16 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 64}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 64 = 0

x_{1, 2} = \frac{- ( - 16 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 16 )}{2 \cdot 1}

\frac{- ( - 16 )}{2 \cdot 1} = 8

x = 8

The solution to the quadratic equation is:

x = 8

Q^{2} - 3092.8 Q + 120000 = 0

- 3 x^{2} - 18 x + 2 = 0

6 x - 12 = - 2 (x + 3) 2 + (2 x + 3) (x - 5)

- 30 - 13 x - 15 x^{2} = 0

y^{2} - 12 y = 28

What are the solutions to the equation (x-6)(x-10)=-4 ?
The solutions to the equation (x-6)(x-10)=-4 are x=8
Find the zeros of (x-6)(x-10)=-4
The zeros of (x-6)(x-10)=-4 are x=8