What are the solutions to the equation x^2+(2x-2)^2=x+6 ?

The solutions to the equation x^2+(2x-2)^2=x+6 are x=2,x=-1/5

Find the zeros of x^2+(2x-2)^2=x+6

The zeros of x^2+(2x-2)^2=x+6 are x=2,x=-1/5

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x^{2} + (2 x - 2)^{2} = x + 6

x = 2, x = - \frac{1}{5}

Decimal Notation

x = 2, x = - 0.2

Solution steps

x^{2} + (2 x - 2)^{2} = x + 6

Expand

x^{2} + (2 x - 2)^{2} : 5 x^{2} - 8 x + 4

5 x^{2} - 8 x + 4 = x + 6

Move

6

to the left side

5 x^{2} - 8 x - 2 = x

Move

x

to the left side

5 x^{2} - 9 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

(- 9)^{2} - 4 \cdot 5 (- 2) = 11

x_{1, 2} = \frac{- ( - 9 ) \pm 11}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 11}{2 \cdot 5}, x_{2} = \frac{- ( - 9 ) - 11}{2 \cdot 5}

x = \frac{- ( - 9 ) + 11}{2 \cdot 5} : 2

x = \frac{- ( - 9 ) - 11}{2 \cdot 5} : - \frac{1}{5}

The solutions to the quadratic equation are:

x = 2, x = - \frac{1}{5}

8 (x^{2} - x) = x^{2} - 3

16 x^{2} + 16 x = - 4

2 b^{2} = 98

x, x^{2} - 7 = 0

x^{2} - 0.8 x - 0.09 = 0

What are the solutions to the equation x^2+(2x-2)^2=x+6 ?
The solutions to the equation x^2+(2x-2)^2=x+6 are x=2,x=-1/5
Find the zeros of x^2+(2x-2)^2=x+6
The zeros of x^2+(2x-2)^2=x+6 are x=2,x=-1/5