What are the solutions to the equation 3x^2+2x-5=2x^2-2 ?

The solutions to the equation 3x^2+2x-5=2x^2-2 are x=1,x=-3

Find the zeros of 3x^2+2x-5=2x^2-2

The zeros of 3x^2+2x-5=2x^2-2 are x=1,x=-3

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3 x^{2} + 2 x - 5 = 2 x^{2} - 2

x = 1, x = - 3

Solution steps

3 x^{2} + 2 x - 5 = 2 x^{2} - 2

Move

2

to the left side

3 x^{2} + 2 x - 3 = 2 x^{2}

Move

2 x^{2}

to the left side

x^{2} + 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 3) = 4

x_{1, 2} = \frac{- 2 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 4}{2 \cdot 1}, x_{2} = \frac{- 2 - 4}{2 \cdot 1}

x = \frac{- 2 + 4}{2 \cdot 1} : 1

x = \frac{- 2 - 4}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 1, x = - 3

(2 x - 3) (x + c) = a x^{2} + b x - 12

3 x^{2} + x - 2 = 0

x^{2} = 7 x + 6

(x - 7)^{2} = - 4

(x - 7)^{2} = 22

What are the solutions to the equation 3x^2+2x-5=2x^2-2 ?
The solutions to the equation 3x^2+2x-5=2x^2-2 are x=1,x=-3
Find the zeros of 3x^2+2x-5=2x^2-2
The zeros of 3x^2+2x-5=2x^2-2 are x=1,x=-3