What are the solutions to the equation 5x^2+8x-17=0 ?

The solutions to the equation 5x^2+8x-17=0 are x=(-4+sqrt(101))/5 ,x=-(4+sqrt(101))/5

Find the zeros of 5x^2+8x-17=0

The zeros of 5x^2+8x-17=0 are x=(-4+sqrt(101))/5 ,x=-(4+sqrt(101))/5

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5 x^{2} + 8 x - 17 = 0

x = \frac{- 4 + 101}{5}, x = - \frac{4 + 101}{5}

Decimal Notation

x = 1.20997 \dots, x = - 2.80997 \dots

Solution steps

5 x^{2} + 8 x - 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 5 ( - 17 )}{2 \cdot 5}

8^{2} - 4 \cdot 5 (- 17) = 2101

x_{1, 2} = \frac{- 8 \pm 2 101}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 8 + 2 101}{2 \cdot 5}, x_{2} = \frac{- 8 - 2 101}{2 \cdot 5}

x = \frac{- 8 + 2 101}{2 \cdot 5} : \frac{- 4 + 101}{5}

x = \frac{- 8 - 2 101}{2 \cdot 5} : - \frac{4 + 101}{5}

The solutions to the quadratic equation are:

x = \frac{- 4 + 101}{5}, x = - \frac{4 + 101}{5}

16 = - 2.7 t^{2} + 60 t + 6.5

(3 y)^{2} = - 18

x^{2} + 14 x - 2 = 0

36 x^{2} = - 60 x - 25

2 x (x - 3) = 9 x^{2} - 7 x

What are the solutions to the equation 5x^2+8x-17=0 ?
The solutions to the equation 5x^2+8x-17=0 are x=(-4+sqrt(101))/5 ,x=-(4+sqrt(101))/5
Find the zeros of 5x^2+8x-17=0
The zeros of 5x^2+8x-17=0 are x=(-4+sqrt(101))/5 ,x=-(4+sqrt(101))/5