What are the solutions to the equation 2p^2-6p-56=0 ?

The solutions to the equation 2p^2-6p-56=0 are p=7,p=-4

Find the zeros of 2p^2-6p-56=0

The zeros of 2p^2-6p-56=0 are p=7,p=-4

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2 p^{2} - 6 p - 56 = 0

p = 7, p = - 4

Solution steps

2 p^{2} - 6 p - 56 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 ( - 56 )}{2 \cdot 2}

(- 6)^{2} - 4 \cdot 2 (- 56) = 22

p_{1, 2} = \frac{- ( - 6 ) \pm 22}{2 \cdot 2}

Separate the solutions

p_{1} = \frac{- ( - 6 ) + 22}{2 \cdot 2}, p_{2} = \frac{- ( - 6 ) - 22}{2 \cdot 2}

p = \frac{- ( - 6 ) + 22}{2 \cdot 2} : 7

p = \frac{- ( - 6 ) - 22}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

p = 7, p = - 4

(4 y + 12)^{2} = 32

6 x^{2} - 6 x + 9 = 0

x^{2} - 2 x + 1 - 2 = 0

- x^{2} = - 25

5 x^{2} = 37 x + 72

What are the solutions to the equation 2p^2-6p-56=0 ?
The solutions to the equation 2p^2-6p-56=0 are p=7,p=-4
Find the zeros of 2p^2-6p-56=0
The zeros of 2p^2-6p-56=0 are p=7,p=-4