What are the solutions to the equation 20x^2-5=0 ?

The solutions to the equation 20x^2-5=0 are x= 1/2 ,x=-1/2

Find the zeros of 20x^2-5=0

The zeros of 20x^2-5=0 are x= 1/2 ,x=-1/2

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20 x^{2} - 5 = 0

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 0.5, x = - 0.5

Solution steps

20 x^{2} - 5 = 0

Move

5

to the right side

20 x^{2} = 5

Divide both sides by

20

x^{2} = \frac{1}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{4}, x = - \frac{1}{4}

\frac{1}{4} = \frac{1}{2}

- \frac{1}{4} = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

x^{2} = 6 x - 66

x = x^{2} - 2 x - 3

4 x^{2} - 20 x - 24 = 0

- 2 x^{2} + 4 x - 12 = 0

(c - 4)^{2} = 81

What are the solutions to the equation 20x^2-5=0 ?
The solutions to the equation 20x^2-5=0 are x= 1/2 ,x=-1/2
Find the zeros of 20x^2-5=0
The zeros of 20x^2-5=0 are x= 1/2 ,x=-1/2