What are the solutions to the equation -x^2=225 ?

The solutions to the equation -x^2=225 are x=15i,x=-15i

Find the zeros of -x^2=225

The zeros of -x^2=225 are x=15i,x=-15i

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- x^{2} = 225

x = 15 i, x = - 15 i

Solution steps

- x^{2} = 225

Divide both sides by

- 1

x^{2} = - 225

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 225, x = - - 225

- 225 = 15 i

- - 225 = - 15 i

x = 15 i, x = - 15 i

x^{2} - 9 = 5

(x + 5)^{2} = 8

x, x f x - y f y = 0

5 y^{2} = 125

2 x^{2} + 8 x = 0

What are the solutions to the equation -x^2=225 ?
The solutions to the equation -x^2=225 are x=15i,x=-15i
Find the zeros of -x^2=225
The zeros of -x^2=225 are x=15i,x=-15i