What are the solutions to the equation 3b^2+3b=6 ?

The solutions to the equation 3b^2+3b=6 are b=1,b=-2

Find the zeros of 3b^2+3b=6

The zeros of 3b^2+3b=6 are b=1,b=-2

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3 b^{2} + 3 b = 6

b = 1, b = - 2

Solution steps

3 b^{2} + 3 b = 6

Move

6

to the left side

3 b^{2} + 3 b - 6 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 3 ( - 6 )}{2 \cdot 3}

3^{2} - 4 \cdot 3 (- 6) = 9

b_{1, 2} = \frac{- 3 \pm 9}{2 \cdot 3}

Separate the solutions

b_{1} = \frac{- 3 + 9}{2 \cdot 3}, b_{2} = \frac{- 3 - 9}{2 \cdot 3}

b = \frac{- 3 + 9}{2 \cdot 3} : 1

b = \frac{- 3 - 9}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

b = 1, b = - 2

x^{2} - 6 = - 4 x - 6

4 x^{2} - 17 x = 15

2 x^{2} - 150 = 0

18 x^{2} + 9 x - 20 = 0

x^{2} - 3 x = 4

What are the solutions to the equation 3b^2+3b=6 ?
The solutions to the equation 3b^2+3b=6 are b=1,b=-2
Find the zeros of 3b^2+3b=6
The zeros of 3b^2+3b=6 are b=1,b=-2