What are the solutions to the equation 3q^2-300q-112500=0 ?

The solutions to the equation 3q^2-300q-112500=0 are q=250,q=-150

Find the zeros of 3q^2-300q-112500=0

The zeros of 3q^2-300q-112500=0 are q=250,q=-150

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3 q^{2} - 300 q - 112500 = 0

q = 250, q = - 150

Solution steps

3 q^{2} - 300 q - 112500 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 300 ) \pm ( - 300 ) ^{2} - 4 \cdot 3 ( - 112500 )}{2 \cdot 3}

(- 300)^{2} - 4 \cdot 3 (- 112500) = 1200

q_{1, 2} = \frac{- ( - 300 ) \pm 1200}{2 \cdot 3}

Separate the solutions

q_{1} = \frac{- ( - 300 ) + 1200}{2 \cdot 3}, q_{2} = \frac{- ( - 300 ) - 1200}{2 \cdot 3}

q = \frac{- ( - 300 ) + 1200}{2 \cdot 3} : 250

q = \frac{- ( - 300 ) - 1200}{2 \cdot 3} : - 150

The solutions to the quadratic equation are:

q = 250, q = - 150

x^{2} + 16 x + 74 = 0

x^{2} + (x + 3)^{2} = 117

4 t^{2} = 108

4 x^{2} + 11 x + 9 = 0

7 x^{2} + 21 x - 20 = 0

What are the solutions to the equation 3q^2-300q-112500=0 ?
The solutions to the equation 3q^2-300q-112500=0 are q=250,q=-150
Find the zeros of 3q^2-300q-112500=0
The zeros of 3q^2-300q-112500=0 are q=250,q=-150