What are the solutions to the equation x^2+16x=-44 ?

The solutions to the equation x^2+16x=-44 are x=2(sqrt(5)-4),x=-2(4+sqrt(5))

Find the zeros of x^2+16x=-44

The zeros of x^2+16x=-44 are x=2(sqrt(5)-4),x=-2(4+sqrt(5))

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x^{2} + 16 x = - 44

x = 2 (5 - 4), x = - 2 (4 + 5)

Decimal

x = - 3.52786 \dots, x = - 12.47213 \dots

Solution steps

x^{2} + 16 x = - 44

Move

44

to the left side

x^{2} + 16 x + 44 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 44}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 44 = 45

x_{1, 2} = \frac{- 16 \pm 4 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 4 5}{2 \cdot 1}, x_{2} = \frac{- 16 - 4 5}{2 \cdot 1}

x = \frac{- 16 + 4 5}{2 \cdot 1} : 2 (5 - 4)

x = \frac{- 16 - 4 5}{2 \cdot 1} : - 2 (4 + 5)

The solutions to the quadratic equation are:

x = 2 (5 - 4), x = - 2 (4 + 5)

x^{2} + 16 x = - 51

3 x^{2} + 20 x + 32 = 0

3 (u - 7)^{2} - 10 = 215

- 4 x^{2} + 32 x + 0 = 0

3 x^{2} - 36 x + 108 = 9

What are the solutions to the equation x^2+16x=-44 ?
The solutions to the equation x^2+16x=-44 are x=2(sqrt(5)-4),x=-2(4+sqrt(5))
Find the zeros of x^2+16x=-44
The zeros of x^2+16x=-44 are x=2(sqrt(5)-4),x=-2(4+sqrt(5))