What are the solutions to the equation 16=-x^2-6x ?

The solutions to the equation 16=-x^2-6x are x=-3-sqrt(7)i,x=-3+sqrt(7)i

Find the zeros of 16=-x^2-6x

The zeros of 16=-x^2-6x are x=-3-sqrt(7)i,x=-3+sqrt(7)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16 = - x^{2} - 6 x

x = - 3 - 7 i, x = - 3 + 7 i

Solution steps

16 = - x^{2} - 6 x

Switch sides

- x^{2} - 6 x = 16

Move

16

to the left side

- x^{2} - 6 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 1 ) ( - 16 )}{2 ( - 1 )}

Simplify

(- 6)^{2} - 4 (- 1) (- 16) : 27 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 7 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 7 i}{2 ( - 1 )}, x_{2} = \frac{- ( - 6 ) - 2 7 i}{2 ( - 1 )}

x = \frac{- ( - 6 ) + 2 7 i}{2 ( - 1 )} : - 3 - 7 i

x = \frac{- ( - 6 ) - 2 7 i}{2 ( - 1 )} : - 3 + 7 i

The solutions to the quadratic equation are:

x = - 3 - 7 i, x = - 3 + 7 i

3 (x - 1)^{2} = 75

x^{2} + x - 20 = 0

\frac{3}{5} (3 p^{2} - 12 p - 10) = 0

2 x^{2} - 6 x + 4 = 0

- 4 x^{2} + 11 x - 6 = 0

What are the solutions to the equation 16=-x^2-6x ?
The solutions to the equation 16=-x^2-6x are x=-3-sqrt(7)i,x=-3+sqrt(7)i
Find the zeros of 16=-x^2-6x
The zeros of 16=-x^2-6x are x=-3-sqrt(7)i,x=-3+sqrt(7)i