What are the solutions to the equation 6x^2+23x-18=0 ?

The solutions to the equation 6x^2+23x-18=0 are x= 2/3 ,x=-9/2

Find the zeros of 6x^2+23x-18=0

The zeros of 6x^2+23x-18=0 are x= 2/3 ,x=-9/2

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6 x^{2} + 23 x - 18 = 0

x = \frac{2}{3}, x = - \frac{9}{2}

Decimal Notation

x = 0.66666 \dots, x = - 4.5

Solution steps

6 x^{2} + 23 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 23 \pm 2 3 ^{2} - 4 \cdot 6 ( - 18 )}{2 \cdot 6}

2 3^{2} - 4 \cdot 6 (- 18) = 31

x_{1, 2} = \frac{- 23 \pm 31}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 23 + 31}{2 \cdot 6}, x_{2} = \frac{- 23 - 31}{2 \cdot 6}

x = \frac{- 23 + 31}{2 \cdot 6} : \frac{2}{3}

x = \frac{- 23 - 31}{2 \cdot 6} : - \frac{9}{2}

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - \frac{9}{2}

3 - x = (x - 1)^{2}

x^{2} - (- 44) x + 1681 = 0

9 x^{2} - 16 x + 7 = 3 x^{2}

3 (6 m - 17) m = 5

4 u^{2} - 15 u - 4 = 0

What are the solutions to the equation 6x^2+23x-18=0 ?
The solutions to the equation 6x^2+23x-18=0 are x= 2/3 ,x=-9/2
Find the zeros of 6x^2+23x-18=0
The zeros of 6x^2+23x-18=0 are x= 2/3 ,x=-9/2