What are the solutions to the equation (3-x)^2+4-2(3-x)=x ?

The solutions to the equation (3-x)^2+4-2(3-x)=x are x= 5/2+i(sqrt(3))/2 ,x= 5/2-i(sqrt(3))/2

Find the zeros of (3-x)^2+4-2(3-x)=x

The zeros of (3-x)^2+4-2(3-x)=x are x= 5/2+i(sqrt(3))/2 ,x= 5/2-i(sqrt(3))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(3 - x)^{2} + 4 - 2 (3 - x) = x

x = \frac{5}{2} + i \frac{3}{2}, x = \frac{5}{2} - i \frac{3}{2}

Solution steps

(3 - x)^{2} + 4 - 2 (3 - x) = x

Expand

(3 - x)^{2} + 4 - 2 (3 - x) : x^{2} - 4 x + 7

x^{2} - 4 x + 7 = x

Move

x

to the left side

x^{2} - 5 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

Simplify

(- 5)^{2} - 4 \cdot 1 \cdot 7 : 3 i

x_{1, 2} = \frac{- ( - 5 ) \pm 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 3 i}{2 \cdot 1}

x = \frac{- ( - 5 ) + 3 i}{2 \cdot 1} : \frac{5}{2} + i \frac{3}{2}

x = \frac{- ( - 5 ) - 3 i}{2 \cdot 1} : \frac{5}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2} + i \frac{3}{2}, x = \frac{5}{2} - i \frac{3}{2}

3 x^{2} + 6 x = 3

x^{2} - x - \frac{7}{4} = 0

4 t^{2} + 8 t = 0

2 (3 x^{2} - 1) = 6 x + 5 x

144 x^{2} - 24 x + 1 = 0

What are the solutions to the equation (3-x)^2+4-2(3-x)=x ?
The solutions to the equation (3-x)^2+4-2(3-x)=x are x= 5/2+i(sqrt(3))/2 ,x= 5/2-i(sqrt(3))/2
Find the zeros of (3-x)^2+4-2(3-x)=x
The zeros of (3-x)^2+4-2(3-x)=x are x= 5/2+i(sqrt(3))/2 ,x= 5/2-i(sqrt(3))/2