What are the solutions to the equation 12x^2-29x-8=0 ?

The solutions to the equation 12x^2-29x-8=0 are x= 8/3 ,x=-1/4

Find the zeros of 12x^2-29x-8=0

The zeros of 12x^2-29x-8=0 are x= 8/3 ,x=-1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

12 x^{2} - 29 x - 8 = 0

x = \frac{8}{3}, x = - \frac{1}{4}

Decimal Notation

x = 2.66666 \dots, x = - 0.25

Solution steps

12 x^{2} - 29 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 29 ) \pm ( - 29 ) ^{2} - 4 \cdot 12 ( - 8 )}{2 \cdot 12}

(- 29)^{2} - 4 \cdot 12 (- 8) = 35

x_{1, 2} = \frac{- ( - 29 ) \pm 35}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 29 ) + 35}{2 \cdot 12}, x_{2} = \frac{- ( - 29 ) - 35}{2 \cdot 12}

x = \frac{- ( - 29 ) + 35}{2 \cdot 12} : \frac{8}{3}

x = \frac{- ( - 29 ) - 35}{2 \cdot 12} : - \frac{1}{4}

The solutions to the quadratic equation are:

x = \frac{8}{3}, x = - \frac{1}{4}

2 x^{2} - 8 - 64 = 0

2 y^{2} - 3 y = 1

- 5 x^{2} + 70 x - 370 = 0

6 x^{2} - 3 x + 7 = 0

x, x^{2} + 9 y^{2} = k

What are the solutions to the equation 12x^2-29x-8=0 ?
The solutions to the equation 12x^2-29x-8=0 are x= 8/3 ,x=-1/4
Find the zeros of 12x^2-29x-8=0
The zeros of 12x^2-29x-8=0 are x= 8/3 ,x=-1/4