What are the solutions to the equation x^2-4x-50=0 ?

The solutions to the equation x^2-4x-50=0 are x=2+3sqrt(6),x=2-3sqrt(6)

Find the zeros of x^2-4x-50=0

The zeros of x^2-4x-50=0 are x=2+3sqrt(6),x=2-3sqrt(6)

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x^{2} - 4 x - 50 = 0

x = 2 + 36, x = 2 - 36

Decimal Notation

x = 9.34846 \dots, x = - 5.34846 \dots

Solution steps

x^{2} - 4 x - 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 50 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 50) = 66

x_{1, 2} = \frac{- ( - 4 ) \pm 6 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 6 6}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 6 6}{2 \cdot 1}

x = \frac{- ( - 4 ) + 6 6}{2 \cdot 1} : 2 + 36

x = \frac{- ( - 4 ) - 6 6}{2 \cdot 1} : 2 - 36

The solutions to the quadratic equation are:

x = 2 + 36, x = 2 - 36

17 x^{2} - 6 x = 0

- 6 x^{2} + 20 x = 0

3 (t - 6)^{2} = - 75

0.01 x^{2} - 0.1 x = 0

36 z^{2} - 64 = 0

What are the solutions to the equation x^2-4x-50=0 ?
The solutions to the equation x^2-4x-50=0 are x=2+3sqrt(6),x=2-3sqrt(6)
Find the zeros of x^2-4x-50=0
The zeros of x^2-4x-50=0 are x=2+3sqrt(6),x=2-3sqrt(6)