What are the solutions to the equation -3(x+3)^2+4=0 ?

The solutions to the equation -3(x+3)^2+4=0 are x= 2/(sqrt(3))-3,x=-2/(sqrt(3))-3

Find the zeros of -3(x+3)^2+4=0

The zeros of -3(x+3)^2+4=0 are x= 2/(sqrt(3))-3,x=-2/(sqrt(3))-3

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- 3 (x + 3)^{2} + 4 = 0

x = \frac{2}{3} - 3, x = - \frac{2}{3} - 3

Decimal Notation

x = - 1.84529 \dots, x = - 4.15470 \dots

Solution steps

- 3 (x + 3)^{2} + 4 = 0

Move

4

to the right side

- 3 (x + 3)^{2} = - 4

Divide both sides by

- 3

(x + 3)^{2} = \frac{4}{3}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = \frac{4}{3} : x = \frac{2}{3} - 3

Solve

x + 3 = - \frac{4}{3} : x = - \frac{2}{3} - 3

The solutions to the quadratic equation are:

x = \frac{2}{3} - 3, x = - \frac{2}{3} - 3

- 2 d + 8.3 \geq 4.7

lo g_{16} (8)

(\frac{t ^{2} + 1}{t ^{2} - 1})^{2}

2 x^{2} = 4 x

What are the solutions to the equation -3(x+3)^2+4=0 ?
The solutions to the equation -3(x+3)^2+4=0 are x= 2/(sqrt(3))-3,x=-2/(sqrt(3))-3
Find the zeros of -3(x+3)^2+4=0
The zeros of -3(x+3)^2+4=0 are x= 2/(sqrt(3))-3,x=-2/(sqrt(3))-3