What are the solutions to the equation 2x^2+3x=77 ?

The solutions to the equation 2x^2+3x=77 are x= 11/2 ,x=-7

Find the zeros of 2x^2+3x=77

The zeros of 2x^2+3x=77 are x= 11/2 ,x=-7

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2 x^{2} + 3 x = 77

x = \frac{11}{2}, x = - 7

Decimal Notation

x = 5.5, x = - 7

Solution steps

2 x^{2} + 3 x = 77

Move

77

to the left side

2 x^{2} + 3 x - 77 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 77 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 77) = 25

x_{1, 2} = \frac{- 3 \pm 25}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 25}{2 \cdot 2}, x_{2} = \frac{- 3 - 25}{2 \cdot 2}

x = \frac{- 3 + 25}{2 \cdot 2} : \frac{11}{2}

x = \frac{- 3 - 25}{2 \cdot 2} : - 7

The solutions to the quadratic equation are:

x = \frac{11}{2}, x = - 7

- 4.9 x^{2} + 13 x + 18 = 0

x^{2} - 2 x + 1 = 0

2 x^{2} + x - 210 = 0

x (x - 12) - 12 (x - 12) = 0

r^{2} - 10 r + 16 = 0

What are the solutions to the equation 2x^2+3x=77 ?
The solutions to the equation 2x^2+3x=77 are x= 11/2 ,x=-7
Find the zeros of 2x^2+3x=77
The zeros of 2x^2+3x=77 are x= 11/2 ,x=-7