What are the solutions to the equation 9x=x^2+4x+4 ?

The solutions to the equation 9x=x^2+4x+4 are x=4,x=1

Find the zeros of 9x=x^2+4x+4

The zeros of 9x=x^2+4x+4 are x=4,x=1

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9 x = x^{2} + 4 x + 4

x = 4, x = 1

Solution steps

9 x = x^{2} + 4 x + 4

Switch sides

x^{2} + 4 x + 4 = 9 x

Move

9 x

to the left side

x^{2} - 5 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 4 = 3

x_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 1}

x = \frac{- ( - 5 ) + 3}{2 \cdot 1} : 4

x = \frac{- ( - 5 ) - 3}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 4, x = 1

3 x^{2} - 6 = 7 x

- 11 - 3 x = - 3 x^{2} - 4

7 j^{2} - 3 j = - j + 9

x^{2} = 7 mod 19

40 - 13 x = - x^{2}

What are the solutions to the equation 9x=x^2+4x+4 ?
The solutions to the equation 9x=x^2+4x+4 are x=4,x=1
Find the zeros of 9x=x^2+4x+4
The zeros of 9x=x^2+4x+4 are x=4,x=1