What are the solutions to the equation x^2+2=5(x^2+1) ?

The solutions to the equation x^2+2=5(x^2+1) are x=(sqrt(3))/2 i,x=-(sqrt(3))/2 i

Find the zeros of x^2+2=5(x^2+1)

The zeros of x^2+2=5(x^2+1) are x=(sqrt(3))/2 i,x=-(sqrt(3))/2 i

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x^{2} + 2 = 5 (x^{2} + 1)

x = \frac{3}{2} i, x = - \frac{3}{2} i

Solution steps

x^{2} + 2 = 5 (x^{2} + 1)

Expand

5 (x^{2} + 1) : 5 x^{2} + 5

x^{2} + 2 = 5 x^{2} + 5

Move

2

to the right side

x^{2} = 5 x^{2} + 3

Move

5 x^{2}

to the left side

- 4 x^{2} = 3

Divide both sides by

- 4

x^{2} = - \frac{3}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{3}{4}, x = - - \frac{3}{4}

- \frac{3}{4} = \frac{3}{2} i

- - \frac{3}{4} = - \frac{3}{2} i

x = \frac{3}{2} i, x = - \frac{3}{2} i

x^{2} + 3 = 2 x^{2} - 1

(x - 6)^{2} - 1 = 0

2 x (x - 2) = 9

x^{2} - 6 x - 8 = 0

x^{2} + 2 x - 99 = 0

What are the solutions to the equation x^2+2=5(x^2+1) ?
The solutions to the equation x^2+2=5(x^2+1) are x=(sqrt(3))/2 i,x=-(sqrt(3))/2 i
Find the zeros of x^2+2=5(x^2+1)
The zeros of x^2+2=5(x^2+1) are x=(sqrt(3))/2 i,x=-(sqrt(3))/2 i